Question

A catapult launches a boulder with an upward velocity of 120 ft/s. The height of the boulder h in feet after t seconds is given by the function h=-16t^2+120t+10. What is the boulders maximum height? How long does it take it to reach the maximum height? Round to the nearest hundreth if neccesary.

Answer 1

@YOLO_KING @Jamesshe67 @AlexandervonHumboldt2

Answer 2

Seconds = \[t=\frac{ 15\pm \sqrt{235 -h} }{ 4 }\]
Height = \[h = -16t^{2} + 120t+10\]