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Geometry 16 Online
OpenStudy (anonymous):

Quadrilateral OPQR is inscribed in circle N, as shown below. What is the measure of ∠ QRO? https://vvsd6966-vvagpeap-ccl.gradpoint.com/Resource/6114359,67D,0,0,0,0,0/Assets/74858_53c6cf40/0902_g3_q1.jpg 41 67 113 139 Woah uh, hmmmm.....I think it's 139.

OpenStudy (anonymous):

@jim_thompson5910

OpenStudy (anonymous):

no its 67

OpenStudy (anonymous):

How did you get that?

jimthompson5910 (jim_thompson5910):

angle O and angle Q are supplementary (since we have an inscribed quadrilateral)

jimthompson5910 (jim_thompson5910):

O + Q = 180 (x+17) + (6x-5) = 180 x = ??

OpenStudy (anonymous):

obvious estimating but hold up ill show steps

OpenStudy (anonymous):

7x + 12 = 180 168/7 24?

OpenStudy (anonymous):

no that's wrong

jimthompson5910 (jim_thompson5910):

yes x = 24 but that's not the last step

jimthompson5910 (jim_thompson5910):

you use x = 24 to compute angle QRO

OpenStudy (anonymous):

oh

OpenStudy (anonymous):

How do I do that?

jimthompson5910 (jim_thompson5910):

on the pic, it shows that QRO is 2x+19

OpenStudy (anonymous):

2x + 19 = 24?

jimthompson5910 (jim_thompson5910):

more like 2x + 19 turns into 2*(24) + 19 you found that x = 24, so replace every 'x' with 24 then evaluate

OpenStudy (anonymous):

oh uh on every formula on qro?

OpenStudy (anonymous):

48+19=67

jimthompson5910 (jim_thompson5910):

yes

OpenStudy (anonymous):

yay

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