OpenStudy (anonymous):

The width of a rectangle is shown below: A coordinate plane with a point A at negative 3, 3 and C at negative 3, negative 2. If the area of the rectangle to be drawn is 20 square units, where should points B and D be located if they lie to the right of points A and C? B(1, 3) and D(1, −2) B(3, 3) and D(3, −2) B(2, 3) and D(2, −2) B(1, 2) and D(1, −3)

3 years ago
OpenStudy (anonymous):

Draw it

3 years ago
OpenStudy (anonymous):

|dw:1421949130007:dw|

3 years ago
OpenStudy (anonymous):

|dw:1421949232842:dw|

3 years ago
OpenStudy (anonymous):

@nelsonjedi

3 years ago
OpenStudy (anonymous):

So what is the distance from A to C?

3 years ago
OpenStudy (anonymous):

-3? @nelsonjedi

3 years ago
OpenStudy (anonymous):

Distance formula between two points is$d= \sqrt{(x2-x1)^{2}+(y2-y1)^{2}}$

3 years ago
OpenStudy (anonymous):

...huh? @nelsonjedi

3 years ago
OpenStudy (anonymous):

You have two points (-3,3) and (-3,-2) we will call them (x1,y1) and (x2,y2)...so to find the distance between these two pints we plug them in the equation above and get $d=\sqrt{(-3-(-3))^{2}+(-3-(-2)^{2}}$

3 years ago
OpenStudy (anonymous):

Which becomes $d=\sqrt{0^{2}+(-5)^{2}}....or .....\sqrt{25}....which.. equals..what..?$

3 years ago
OpenStudy (anonymous):

Do you understand?

3 years ago
OpenStudy (anonymous):

i still dont know??

3 years ago
OpenStudy (anonymous):

no @nelsonjedi

3 years ago