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Integration of:
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\[\int\limits_{1}^{2} \frac{ e^{\frac{ 1 }{ x }} }{ x^{2} }dx\]
let u = 1/x and you can get the answer
don't forget changing the limits
I'll give it a try, but what about the x on the bottom? and yes I'll change the limits once I'm on track
u =1/x --> du = -(1/2x^2) dx , that is \(-2du = \dfrac{1}{x^2} dx\) , right? no more denominator. :)
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thank you :)
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