Question

Help,solving the area of a figure in terms of s. Helpful steps please. (Figure attached)

Answer 1

HI!!

Answer 2

you know the area of a triangle is one half base times height right?
also the height of that triangle is \(s\) so the only question is, what is the base??

Answer 3

would that then make it be s^2 x the square root of 3/2

Answer 4

the ratios of a 30 - 60 - 90 triangle area
\[1:\sqrt3:2\]so if the short sides is \(s\) then the long side (the base) is \(\sqrt2 s\)

Answer 5

oops i made a typo long side is \(\sqrt3 s\)

Answer 6

so yeah what you said
area is
\[\frac{\sqrt3 s^2}{2}\]

Answer 7

Thank you for your explanation cleared up my confusion!

Answer 8

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