Complete the equation for the linear function whose graph contains the points (2, 5) and (3, 0). y − = (x − 2)
I think its y-5=3(x-2)?
calculate the slope from those 2 points, and use the point (2,5) in y - y1 = m(x-x1)
you can start by finding the slope
You have the point (x1,y1) = (2,5) right the slope is the difference in the 2 y's over the diference in the 2 x's
\[slope = \frac{ 0-5 }{ 3-2 }\]
-5?
yea
So y-(-5)=3(x-2)
Given: y − ? = ? * (x − 2) where did you get the 3 from
Complete the equation for the linear function whose graph contains the points (2, 5) and (3, 0). lol *facepalm* i messed up huh? Is this it So y-(-5)=2(x-2)
point (x1,y1) = (2,5) slope m = -5 ----------------- Point-slope formula y - y1 = m*(x-x1)
y - 5 = -5*(x-2)
:| I'm dumb huh?
hah, no you are learning
Lol i have 2 more thank god!
k
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