Complete the equation for the linear function whose graph contains the points
(2, 5) and (3, 0).
y − = (x − 2)
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OpenStudy (twizttiez):
I think its y-5=3(x-2)?
OpenStudy (danjs):
calculate the slope from those 2 points, and use the point (2,5) in
y - y1 = m(x-x1)
OpenStudy (triciaal):
you can start by finding the slope
OpenStudy (danjs):
You have the point (x1,y1) = (2,5) right
the slope is the difference in the 2 y's over the diference in the 2 x's
OpenStudy (danjs):
\[slope = \frac{ 0-5 }{ 3-2 }\]
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OpenStudy (twizttiez):
-5?
OpenStudy (danjs):
yea
OpenStudy (twizttiez):
So y-(-5)=3(x-2)
OpenStudy (danjs):
Given: y − ? = ? * (x − 2)
where did you get the 3 from
OpenStudy (twizttiez):
Complete the equation for the linear function whose graph contains the points
(2, 5) and (3, 0). lol *facepalm* i messed up huh? Is this it So y-(-5)=2(x-2)
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OpenStudy (danjs):
point (x1,y1) = (2,5)
slope m = -5
-----------------
Point-slope formula
y - y1 = m*(x-x1)
OpenStudy (danjs):
y - 5 = -5*(x-2)
OpenStudy (twizttiez):
:| I'm dumb huh?
OpenStudy (danjs):
hah, no you are learning
OpenStudy (twizttiez):
Lol i have 2 more thank god!
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