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Complete the equation for the linear function whose graph contains the point (−1, 2) and has a slope of 0.9. y = x +
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same thing.. use the point-slope formula y - y1 = m*(x-x1) point(x1,y1) slope m
just put the values into the equation.
y = 0.9x + 2.9 ah hah!
y - 2 = 0.9* ( x - (-1) )
y - 2 = 0.9x + 0.9 y = 0.9x + 0.9 + 2
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So i was wrong again D: no!!!
using the point slope form, you get y - 2 = 0.9 *(x + 1) then distribute the right, and add 2 to both sides y - 2 = 0.9x + 0.9 y = 0.9x + 2.9
Gah Dan i was right you fooled me curses!
oh, i didn't see that, i was looking for the precess to get to that.. sorry
No prob xD
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