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Mathematics 15 Online
OpenStudy (girlover):

Can someone help me understand how to do this problem?

OpenStudy (girlover):

OpenStudy (girlover):

@Nnesha

OpenStudy (danjs):

when x=0, y=1 that looks like enough info to select an answer, only one satisfies the point (0,1)

OpenStudy (girlover):

so i just plug in the numbers to the variables?

OpenStudy (danjs):

For this one, there is only one answer that goes through the point (0,1) . All the other info really isnt needed.

OpenStudy (girlover):

oh ok but i still dont know how to get the answer like what is the process? is there a formula i go by?

OpenStudy (danjs):

The vertical asmytotes are where the denominator will = 0, x^2-9 = 0 x=+or-3

OpenStudy (danjs):

The first thing i did was plug in the point (0,1) that they gave you f(0) = 1

OpenStudy (danjs):

When x=0, only one of the answers equals 1.

OpenStudy (girlover):

oh so A because 3^2=9 and 9/9=1

OpenStudy (danjs):

The point they give is (0,1) When x=0 , y = f(0) = 1 \[f(1) = \frac{ -9 }{ 0^2-9 } = \frac{ -9 }{ -9 } = 1\]

OpenStudy (danjs):

Choice A , when x=0, would be \[f(0) = \frac{ 9}{ 0-9} = \frac{ 9 }{ -9 } = -1\] not 1, so not the answer

OpenStudy (girlover):

so C bc that wud get 1 instead of -1

OpenStudy (danjs):

Choice B , X=0, then \[f(x) = \frac{ 1 }{ 0 } = undefined\]

OpenStudy (danjs):

right, choice C is the only function that goes through the point x=0, y=1

OpenStudy (girlover):

oh i see now...thank you so much..i understand the process now ^.^

OpenStudy (danjs):

this one was pretty easy, you didn't have to know anything about the vertical or horizontal asymtotes to get the answer...

OpenStudy (girlover):

hmm well i may need help on some others when they arent this easy so can i just tag you in them if i need help on understanding how that process is?

OpenStudy (danjs):

sure

OpenStudy (girlover):

ok i found one that is a bit more difficult i will make a new post tho to give you another metal for your cooperation.

OpenStudy (danjs):

k

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