Can someone help me understand how to do this problem?
@Nnesha
when x=0, y=1 that looks like enough info to select an answer, only one satisfies the point (0,1)
so i just plug in the numbers to the variables?
For this one, there is only one answer that goes through the point (0,1) . All the other info really isnt needed.
oh ok but i still dont know how to get the answer like what is the process? is there a formula i go by?
The vertical asmytotes are where the denominator will = 0, x^2-9 = 0 x=+or-3
The first thing i did was plug in the point (0,1) that they gave you f(0) = 1
When x=0, only one of the answers equals 1.
oh so A because 3^2=9 and 9/9=1
The point they give is (0,1) When x=0 , y = f(0) = 1 \[f(1) = \frac{ -9 }{ 0^2-9 } = \frac{ -9 }{ -9 } = 1\]
Choice A , when x=0, would be \[f(0) = \frac{ 9}{ 0-9} = \frac{ 9 }{ -9 } = -1\] not 1, so not the answer
so C bc that wud get 1 instead of -1
Choice B , X=0, then \[f(x) = \frac{ 1 }{ 0 } = undefined\]
right, choice C is the only function that goes through the point x=0, y=1
oh i see now...thank you so much..i understand the process now ^.^
this one was pretty easy, you didn't have to know anything about the vertical or horizontal asymtotes to get the answer...
hmm well i may need help on some others when they arent this easy so can i just tag you in them if i need help on understanding how that process is?
sure
ok i found one that is a bit more difficult i will make a new post tho to give you another metal for your cooperation.
k
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