Question

thanks

Answer 1

cotx=cosx/sinx

Answer 2

cotx=1/tanx yes!

Answer 3

thanks!!

Answer 4

that's not the same question

Answer 5

oh yeah its the same lol
thought you threw a different question there

Answer 6

yes!

Answer 7

thanks!!

Answer 8

are you just guessing lol
use 1+tan^2x=sec^2x to find the right answer

Answer 9

lol no haha

Answer 10

no don't lie to me, i know you are guessing heheh

Answer 11

haha i try jk

Answer 12

so we have tan^2x=1/2 then 1+tan^2x=3/2
so we got sec^2x=3/2 ====> \[\large \sec x=+-\sqrt{\frac{3}{2}}\]

Answer 13

sorry i had to look for plus or minus thingy in latex hehe damn
didn't use it before

Answer 14

but it not my chioce tho

Answer 15

you have it in your choices hehe it root(6)/2

Answer 16

with +-

Answer 17

lol my bad haha

Answer 18

you have to get your roots hehe
otherwise you gonna have a lot of problem with them later :)

Answer 19

thanks how about the other one

Answer 20

i answered you all the questions already, how about you try with that yourself
see your notes check what you can learn there :)

Answer 21

[ sqrt(6)/4 ] + [ sqrt(2) / 4 ]
[sqrt(6) + sqrt(2)] / 4 its right

Answer 22

you missed it hehe

Answer 23

what why lol

Answer 24

oh no you are correct!
but how did you get it? show the work

Answer 25

lol i did it on paper haha

Answer 26

no you just guessed again yes? haha

Answer 27

noooooooo lol i did really do it this time haha

Answer 28

okay dokie:)
i hope you did it ^^

Answer 29

i did trust me lol

Answer 30

anyways the trick is to write 15 as 15=45-30 which we know
the use the identity cos(a-b)

Answer 31

okay i trust you this time lol

Answer 32

good luck