Ask your own question, for FREE!
Mathematics 16 Online
OpenStudy (anonymous):

Solve equation log(2x + 1) = 1 + log (x-2)

OpenStudy (anonymous):

the first step I would take is to subtract log(x-2) from both sides

OpenStudy (anonymous):

then you can use, log(a) - log(b) = log(a/b)

OpenStudy (anonymous):

use the property $$log_{e}(a) = b$$ you can rewrite as $$e^{b} = a$$ this property works for any base, just replace e with the base

OpenStudy (anonymous):

@sabmar28 can you take it from there?

OpenStudy (anonymous):

good name @sabmar28

OpenStudy (anonymous):

THANKS

OpenStudy (anonymous):

@sabmar28 if you need help @mention me or msg me

OpenStudy (anonymous):

(2x+1)/(x-2)=10

OpenStudy (anonymous):

ok that looks good, so now what would you do?

OpenStudy (anonymous):

log(x) can be base 10 or base e, kinda confusing, sorry

OpenStudy (anonymous):

http://www.purplemath.com/modules/logs3.htm see the warning here

OpenStudy (anonymous):

can apparently be base-2 also? lol

OpenStudy (anonymous):

anyways what would be the next step?

OpenStudy (anonymous):

THE ANSWER IS 21/8

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!