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Solve equation log(2x + 1) = 1 + log (x-2)
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the first step I would take is to subtract log(x-2) from both sides
then you can use, log(a) - log(b) = log(a/b)
use the property $$log_{e}(a) = b$$ you can rewrite as $$e^{b} = a$$ this property works for any base, just replace e with the base
@sabmar28 can you take it from there?
good name @sabmar28
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THANKS
@sabmar28 if you need help @mention me or msg me
(2x+1)/(x-2)=10
ok that looks good, so now what would you do?
log(x) can be base 10 or base e, kinda confusing, sorry
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can apparently be base-2 also? lol
anyways what would be the next step?
THE ANSWER IS 21/8
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