Help me factor this expression 3(x^3+4xy-3x^2y-12y) @AnswerMyQuestions
Are you sure the question is correct?? I guess the last term should be 12y^2 Can u just check?
Well the first question was Rewrite the expression so that the GCF is factored completely. Show the steps of your work. And the expression to do this with was 3x^3y + 12xy - 9x^2y - 36y. And that is how I got 3(x^3+4xy-3x^2y-12y).
Is that correct?
3(x^3y+4xy-3x^2y-12y)
Should I just copy and paste the questions?
So my first answer was correct?
3x^3y + 12xy - 9x^2y - 36y 3x^3y - 9x^2y + 12xy - 36y (3x^3y - 9x^2y) + (12xy - 36y) 3x^2y(x - 3) + 12y(x - 3)
Hope this is clear and you can do the rest... if not let me know..
Just rearranged and took the common facotrs
So now I just distribute
right?
yeah...
take (x-3) as common factor from both terms...
I got (3x^3-9x^2y)+(12yx-36)
nope... that's not the way
Is it because I forgot the y?
(x - 3) (3x^2y + 12y) (x - 3) (3y) (x^2 + 4) (3y) (x - 3) (x^2 + 4)
Is that clear?
Yes it is, so there is simplified?
yep... this is the final answer :)
Thank you for helping me, I really needed it and I appreciate it/
yeah.. its my pleasure helping u
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