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Algebra 21 Online
OpenStudy (anonymous):

Help me factor this expression 3(x^3+4xy-3x^2y-12y) @AnswerMyQuestions

OpenStudy (midhun.madhu1987):

Are you sure the question is correct?? I guess the last term should be 12y^2 Can u just check?

OpenStudy (anonymous):

Well the first question was Rewrite the expression so that the GCF is factored completely. Show the steps of your work. And the expression to do this with was 3x^3y + 12xy - 9x^2y - 36y. And that is how I got 3(x^3+4xy-3x^2y-12y).

OpenStudy (anonymous):

Is that correct?

OpenStudy (midhun.madhu1987):

3(x^3y+4xy-3x^2y-12y)

OpenStudy (anonymous):

Should I just copy and paste the questions?

OpenStudy (anonymous):

So my first answer was correct?

OpenStudy (midhun.madhu1987):

3x^3y + 12xy - 9x^2y - 36y 3x^3y - 9x^2y + 12xy - 36y (3x^3y - 9x^2y) + (12xy - 36y) 3x^2y(x - 3) + 12y(x - 3)

OpenStudy (midhun.madhu1987):

Hope this is clear and you can do the rest... if not let me know..

OpenStudy (midhun.madhu1987):

Just rearranged and took the common facotrs

OpenStudy (anonymous):

So now I just distribute

OpenStudy (anonymous):

right?

OpenStudy (midhun.madhu1987):

yeah...

OpenStudy (midhun.madhu1987):

take (x-3) as common factor from both terms...

OpenStudy (anonymous):

I got (3x^3-9x^2y)+(12yx-36)

OpenStudy (midhun.madhu1987):

nope... that's not the way

OpenStudy (anonymous):

Is it because I forgot the y?

OpenStudy (midhun.madhu1987):

(x - 3) (3x^2y + 12y) (x - 3) (3y) (x^2 + 4) (3y) (x - 3) (x^2 + 4)

OpenStudy (midhun.madhu1987):

Is that clear?

OpenStudy (anonymous):

Yes it is, so there is simplified?

OpenStudy (midhun.madhu1987):

yep... this is the final answer :)

OpenStudy (anonymous):

Thank you for helping me, I really needed it and I appreciate it/

OpenStudy (midhun.madhu1987):

yeah.. its my pleasure helping u

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