Inverse Variation Help Please!!!
The pair of points is on the graph of an inverse variation. Find the missing value.
(2.4, 3) and (5, y)
A) 1.44
B) 1
C) 6.25
D) 0.69
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OpenStudy (godlovesme):
sorry idk this stufff :( @Nnesha help :) he/she is genius
OpenStudy (ilovecake):
Let's solve the first point and by doing so we have to find the constant of variation which y = k/x and 3 = k/2.4. Using this same constant of variation with the second point,
2.4 *3=7.2
y = k/x
y = 7.2/5
y = ?
OpenStudy (anonymous):
1.44? @Ilovecake
OpenStudy (ilovecake):
yup
OpenStudy (godlovesme):
@Ilovecake u r awesome i'm sooo fanning u :)
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OpenStudy (anonymous):
Thank you SO much! Can you help me with a few more?? @Ilovecake
OpenStudy (ilovecake):
yea sure
OpenStudy (ilovecake):
ok
OpenStudy (anonymous):
Find the constant of variation k for the inverse variation. Then write an equation for the inverse variation.
y = 5 when x = 7.5
A) k = 15; xy = 1.5
B) k = 37.5; xy = 37.5
C) k = 37.5; 37.5y = x
D) k = 2.5; y = 2.5/x
OpenStudy (anonymous):
I know the answer isn't A or D...
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OpenStudy (ilovecake):
\[y = 37 \over x \] and now we can check. 5= 37.5
OpenStudy (ilovecake):
37.5 over 7.5
OpenStudy (anonymous):
I don't see that option though...
OpenStudy (anonymous):
Would it be B?
OpenStudy (ilovecake):
It would be option C.....
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OpenStudy (anonymous):
C was incorrect... but can you help me with some more?