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Physics
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calculus- Integrals with e in it
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how does \[\frac{ 1 }{ 7} e^7\theta \sin 6 \theta-\frac{ 6 }{ 49 } e^(7\theta) \cos 6\theta+ \frac{ 36 }{56 } e^(7\theta)- \cos 6 \theta = \frac{ 1 }{ 85 }e^(7\theta) \cos 7\theta + 7e^(7 \theta) \sin 7 \theta\]
the e's are all raised to 7theta
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