Ask your own question, for FREE!
Mathematics 13 Online
OpenStudy (anonymous):

Find the tangent ratio of angle Θ. Hint: Use the slash symbol ( / ) to represent the fraction bar, and enter the fraction with no spaces.

OpenStudy (anonymous):

please help?

OpenStudy (anonymous):

@satellite73 @phi

OpenStudy (anonymous):

can u help? @Loser66

OpenStudy (loser66):

No, I can't since I can't open the file

OpenStudy (anonymous):

oh hold on ill make it easier

OpenStudy (anonymous):

OpenStudy (loser66):

hey, it is just apply the definition of tangent . that is \(tan(\theta)= \dfrac{opposite}{adjacent}\) , just plug number in.

OpenStudy (anonymous):

what @Loser66 said

OpenStudy (anonymous):

@Loser66 @satellite73 so just divide 12/5?

OpenStudy (anonymous):

@Directrix

OpenStudy (anonymous):

@bibby

Directrix (directrix):

The tangent of an angle is the ratio of the length of the opposite leg to that of the adjacent leg.

OpenStudy (anonymous):

this is basically all i know about this problem :/ http://assets.openstudy.com/updates/attachments/52d6f080e4b0cb9c2bfc5602-reneestacha-1389818263518-mooo.jpg

OpenStudy (anonymous):

so that would be what i put on the answer box?

OpenStudy (anonymous):

seems too easy im over thinking it D:

OpenStudy (anonymous):

12/5 is correct

OpenStudy (anonymous):

You are over thinking it

OpenStudy (anonymous):

ok thank you guys! :) and can you help me on one more i just need to make sure its right.

OpenStudy (anonymous):

Yeah sure!

OpenStudy (anonymous):

If the sin 90° is 1, then the cos ____ °= _____.

OpenStudy (anonymous):

90° ; 1 over 2 0° ; square root 2 over 2 90° ; square root 3 over 2 0° ; 1 << thats my answer

OpenStudy (anonymous):

the Q marks are the degrees

Directrix (directrix):

Sine and Cosine are cofunctions where "co" is code for complementary.

Directrix (directrix):

0° ; 1 << thats my answer and, also mine.

OpenStudy (anonymous):

ok thank you :)

Directrix (directrix):

You are welcome.

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!