Brass is an alloy of copper and zinc. Bronze is an alloy containing 80% copper, 4% of zinc and 16% of tin. A fused mass of brass and bronze is found to contain 74% of copper, 16% zinc, and 10% of tin. The ratio of copper to zinc in brass is? a.) 64% and 36% b.) 33% and 67% c.) 50% and 75% d.)35% and 65%
@amistre64
if this is possible to solve, id say we simply remove the bronze ratio to determine whats left
can u elaborate
we are given that bronze has a given ratio pf parts, and that the combined mass contains bronze in it, remove the bronze part by an appropriate ratio
since we have no tin in brass, what is the proper scalar to get .16t = .10 ?
t=5/8
then 5/8 of the copper is bronze, and 5/8 of the zinc is bronze remove them to find whats left is what comes to mind
u mean 74-5/8(74) like this ?
.74 * 5/8 = bronze so .74 * 3/8 = brass copper and likewise, .16*3/8 should give us brass zinc
74 - 5/8(74) seems fair as well. took some time to process what you meant :)
0.74*3/8=0.277
so how do i convert 0.277 in %
.277 is just how much copper we have left over, how much zinc is left over?
zince 0.16*3/8=0.06
Bronze contains 80% copper 4% of zinc 16% of tin A fused mass of brass and bronze is found to contain .74 of copper = .80 bronze + x brass .16 of zinc = .04 bronze + y brass .10 of tin = .16 bronze + 0 brass the tin row can solve for bronze, 5/8 .74 of copper = .80*5/8 + x brass .16 of zinc = .04*5/8 + y brass .10 of tin = .16*5/8 + 0 brass now we have 2 equations in 2 unknowns
something along these lines should work out
book gives answer 64% copper and 36% zinc
thats what i get as well
.74 = .80*5/8 + x*3/8 .16 = .04*5/8 + y*3/8 .10 = .16*5/8 x and y are both solvable
thanks very much
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