The sum of three numbers is 122. The third number is 8 less than the first. The second number is 4 times the third. What are the numbers?
x + 4(8-x) + 8-x = 122 this is the equation
Ok, how do i get x?
what would be your first step in solving for x?
i dont know
if i give you 2x + 4 = 10, could you solve for x?
x=3?
thats correct, how did you get that answer?
btw x = 3 may or may not be what x equals in the other equation
that is just a side example
I see
but how did you get the value of x in my example?
10-4=6 6/2=3
ah very nice so you do know how to do this
ok so do the same thing for the other equation
isolate x on one side of the equation
first off i would eliminate all the parenthesis by distributing, can you do that and rewrite it?
x + 4(8-x) + 8-x = 122, distribute the middle term, and rewrite
lol yeah thats true, so why were u asking how to find x if you know how? lol anyways nice, now just plug x back in to each term to see what each number is
Ok
first number = x second number = 4(8-x) third number = 8-x
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