Mathematics
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OpenStudy (anonymous):
a is the point (0,-2)
b is the point (-4,2)
c is the point (0,,3)
find an equation of the line that passes through C and is parallel to AB
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OpenStudy (bibby):
use point-slope form using the slope of AB and the coordinates in C
the slope fo rmula is \(\large m=\frac{y_2-y_1}{x_2-x_1}\)
OpenStudy (anonymous):
do you mean
-2-2 over 0-4 =-4/4
OpenStudy (bibby):
\(x_1,y_1)\) is (0,-2)
\(x_2,y_2)\) is (-4,2)
OpenStudy (bibby):
if we do it in your order it'd be
-2-2
----------
0--4
(and not 0-4)
OpenStudy (anonymous):
-4/4 =-1 or gradient of -x
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OpenStudy (bibby):
-1 is the slope of the line we want (parallel to the line containing A and B)
now we plug it into the point slope form \(y-y_1=m(x-x_1)\)
OpenStudy (anonymous):
so y-3=-Cx-0)
OpenStudy (bibby):
"c is the point (0,,3)"
I assume you meant y-3=-1(x-0)=y-3=-x
OpenStudy (anonymous):
yes
OpenStudy (bibby):
well get it into slope intercept form to finish
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OpenStudy (anonymous):
how
OpenStudy (bibby):
y=mx+b
OpenStudy (bibby):
solve for y
OpenStudy (anonymous):
?
OpenStudy (anonymous):
whats the final answer
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OpenStudy (bibby):
y-3=-x
solve for y...
OpenStudy (anonymous):
y=3x???????
OpenStudy (bibby):
3-x or -x+3
OpenStudy (anonymous):
so the final answer is -x+3
OpenStudy (bibby):
yeah
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OpenStudy (anonymous):
thank you very much