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use double-angle,power reducing,half-angle to solve. TAN 112.5°
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HI!!
\(112.5^\circ\) is half of \(225^\circ\) so you can use the half angle formula with \(225^\circ\)
\[\tan(11.25^\circ)=\frac{1-\cos(225^\circ)}{\sin(225^\circ)}\] would work
yes thank you !
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