The table shows the results of drawing colored marbles from a bag.
Based on theoretical probability, which is the best prediction for the number of times a red marble would be drawn in 1000 trials?
A.
100
B.
125
C.
167
D.
200
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OpenStudy (anonymous):
OpenStudy (anonymous):
@pooja195
pooja195 (pooja195):
which do you think and explain :)
OpenStudy (anonymous):
i don't know what it is tat why i need help
OpenStudy (anonymous):
thats
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OpenStudy (anonymous):
i don't know how to figure it out
pooja195 (pooja195):
maybe @Nnesha can help? i hope
OpenStudy (anonymous):
@Nnesha
pooja195 (pooja195):
@dtan5457
OpenStudy (anonymous):
please help
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OpenStudy (anonymous):
i really need help
OpenStudy (anonymous):
@Beleaguer
OpenStudy (anonymous):
do you know how to get the answer?
Nnesha (nnesha):
okay so probability...............
Nnesha (nnesha):
first add number of all marbles toghter
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OpenStudy (anonymous):
ok, i got 40
OpenStudy (anonymous):
@Nnesha
Nnesha (nnesha):
okay so how many are red ??
OpenStudy (anonymous):
there are 5 red
Nnesha (nnesha):
yes so 5/40 reduce da fraction
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OpenStudy (anonymous):
it is 1/8
Nnesha (nnesha):
1/8 times 1000= ??
OpenStudy (xapproachesinfinity):
hmm weird number of times drawn
how many trials that thing represent
Nnesha (nnesha):
hmmmmmm!!
OpenStudy (xapproachesinfinity):
so this is saying we don't have equally likely probabilities
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OpenStudy (anonymous):
1/8*1000=125
OpenStudy (anonymous):
so the answer is b.125
OpenStudy (anonymous):
@Nnesha
OpenStudy (xapproachesinfinity):
i want to say what @Nnesha did is good
but not sure why they give you that other part for number times the marble is drawn
Nnesha (nnesha):
hmm i guess right @xapproachesinfinity what you think ?? :D
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OpenStudy (xapproachesinfinity):
hmm thinking...
but i do think that your answer is good :)
OpenStudy (xapproachesinfinity):
you need to make a new question dear :)
OpenStudy (anonymous):
oh ok sorry
OpenStudy (xapproachesinfinity):
:)
OpenStudy (xapproachesinfinity):
I go with @Nnesha for this answer :)
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Nnesha (nnesha):
hh okay i hope that's right :D
OpenStudy (anonymous):
on the first question or second?
OpenStudy (xapproachesinfinity):
on the first of course :)
the second repost it separately ^^
OpenStudy (anonymous):
i wisi i can give you both medal but i can't so who do i give the medal too?