which of the following are trigonometric indentities (check all that apply).
a. 4cos(x)sin(x) = 2cos(x)+1-2sin(x)
b. tan(x)cos(x)csc(x) = 1
c. (csc(x) - sin(x))/csc(x) = cos^2(x)
d. 1 + cot(x) tan(y) = (sin(x+y))/sin(x)cos(y)
Please help! I am really bad with identities!
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OpenStudy (xapproachesinfinity):
b is an identity
just check if the left had side equal to right hand side
there is more than one
OpenStudy (xapproachesinfinity):
c as well is an identity
OpenStudy (anonymous):
but how would you figure it out
OpenStudy (anonymous):
because i would like to know how to prove and show an equation is an identity @xapproachesinfinity
OpenStudy (xapproachesinfinity):
use the identities you know
like csc=1/sin
tan=sin/cos
...
you need to know the basic stuff
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OpenStudy (xapproachesinfinity):
a is not good
it is not an identity
4cosxsinx=2sin2x this cannot equal that left side stuff
OpenStudy (xapproachesinfinity):
of course you need to know that 2cosxsinx=sin2x
OpenStudy (xapproachesinfinity):
well now you have only one to work on
recall
sin(a+b)=sinacosb+sinbcosa
OpenStudy (anonymous):
yes
OpenStudy (xapproachesinfinity):
use that x=a y=b
see if that satisfies the left hand side
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OpenStudy (anonymous):
it doesn't
OpenStudy (xapproachesinfinity):
i agree
OpenStudy (xapproachesinfinity):
i think you are done:)
OpenStudy (anonymous):
so then the answers are b and c ?
OpenStudy (anonymous):
@xapproachesinfinity
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OpenStudy (xapproachesinfinity):
yes are you not paying attention hehe
OpenStudy (anonymous):
d is also an answer @xapproachesinfinity
OpenStudy (xapproachesinfinity):
No
OpenStudy (mathmath333):
one trick to check that is to put arbitrary values for x
example
\(\large\tt \begin{align} \color{black}{x=45^{\circ}\hspace{.33em}\\~\\}\end{align}\)
and see if \(\bf LHS =RHS\)