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OpenStudy (henrietepurina):
A basketball is thrown upwards. The height f(t), in feet, of the basketball at time t, in seconds, is given by the following function:
f(t) = -16t^2 + 16t + 32
Which of the following is a reasonable domain of the graph of the function when the basketball falls from its maximum height to the ground?
0.5 < t < 1
0.5 < t < 2
1 < t < 2
1 < t < 1.5
OpenStudy (henrietepurina):
@jagr2713
jagr2713 (jagr2713):
highest point in this case should be the vertex and the rightest zero x value of vertex = -b/2a given ax^2 + bx + c
jagr2713 (jagr2713):
plug in and that'll be the first point, the other point would be solve -16x^2 + 16x + 32 = 0 and take the positive answer, that'll be your other point
OpenStudy (henrietepurina):
ok ill try...
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OpenStudy (henrietepurina):
the 2nd point is 2...
OpenStudy (henrietepurina):
can you help me get the first one?
jagr2713 (jagr2713):
so if its 2 then what can we eliminate
OpenStudy (henrietepurina):
a and d
jagr2713 (jagr2713):
solve this -16x^2 + 16x + 32 = 0
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jagr2713 (jagr2713):
first factor out the greatest common factor (-16) then factor... do you know how to do that?
OpenStudy (henrietepurina):
somewhat... but I'll need help
jagr2713 (jagr2713):
you will get 0=-16(t+0.5)+6
OpenStudy (henrietepurina):
ok, and by using my amazing brain smarts, I see a 0.5 in there
OpenStudy (henrietepurina):
:D
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OpenStudy (henrietepurina):
making me think it might be b?
jagr2713 (jagr2713):
Yes :D
OpenStudy (henrietepurina):
thanks :D
jagr2713 (jagr2713):
yw
OpenStudy (funnyguy2):
is this a test
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OpenStudy (henrietepurina):
why?
OpenStudy (funnyguy2):
just tell me first
OpenStudy (henrietepurina):
no, my algebra 1 homework....
OpenStudy (funnyguy2):
ok then your fine
OpenStudy (henrietepurina):
why would you ask that?
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jagr2713 (jagr2713):
why ?@funnyguy2
OpenStudy (henrietepurina):
he/she left :|
OpenStudy (funnyguy2):
your not allowed to get help on a test
jagr2713 (jagr2713):
??? where does it say that
OpenStudy (henrietepurina):
mhm... cool, but as you know... this is NOT a test
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OpenStudy (henrietepurina):
and yeah... where does it say that?
OpenStudy (henrietepurina):
hello @funnyguy2 ?
OpenStudy (funnyguy2):
@pooja195 are you allowed to help someone on a test
OpenStudy (funnyguy2):
@sleepyjess
OpenStudy (funnyguy2):
@TheSmartOne
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OpenStudy (sleepyjess):
It is not a test, they already said that.
OpenStudy (henrietepurina):
exactly....
OpenStudy (funnyguy2):
one question per post please
OpenStudy (henrietepurina):
but what he asked was, are you allowed to help IF it was a test?
OpenStudy (henrietepurina):
are you kidding @funnyguy2 ?
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pooja195 (pooja195):
@funnyguy2 it is certainly not allowed unless youve made a mistake by accidently halping them without knowing its a test i am guilty of that but if you have helped knowing its a test you can land in some serious trouble
OpenStudy (henrietepurina):
ok thanks for clearing that up :D
jagr2713 (jagr2713):
close question pls :D
OpenStudy (henrietepurina):
sure can do :D
TheSmartOne (thesmartone):
You guys asked where that is? :P
Let me pull it up :)
Even though I know you weren't cheating :)
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TheSmartOne (thesmartone):
The term and conditions are something you agreed to when you first signed up! And in the TaC (Terms and Conditions) it has near the bottom:
http://prntscr.com/5wy0p9
Don't want to copy-paste otherwise it looks longer than it is... lol
Anyways here is the whole TaC:
http://openstudy.com/terms-and-conditions