Select the equation of a line that is perpendicular to the line on the graph and passes through the point (3, 2).
y = 1 over 3 x + 3
y = -1 over 3x + 3
y = 3 x + 2
y = - 1 over 3 x + 2
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OpenStudy (anonymous):
OpenStudy (anonymous):
@Nnesha
Nnesha (nnesha):
okay again first you have to find slope of the graph
OpenStudy (anonymous):
ok so how will i do it with this @Nnesha
OpenStudy (anonymous):
@Nnesha
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Nnesha (nnesha):
you can pick two points and use slope formula to find slope
OpenStudy (anonymous):
please show me srry i am kinda rushing @Nnesha
Nnesha (nnesha):
okay so do you know slope is rise/run then see how many points are going up and how many points are you going right
this is another way to find slope
OpenStudy (anonymous):
so my slope would be 3/2 right
Nnesha (nnesha):
nope try that again see how many points are going right side
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OpenStudy (anonymous):
how do i count the points
Nnesha (nnesha):
if you look at this u can where its make right triangle
nw see how any step are going right
OpenStudy (anonymous):
3 points then @Nnesha
Nnesha (nnesha):
yes that's right now perpendicular slope should be ??
OpenStudy (anonymous):
ummm idk may you show me again like you do the first time @Nnesha
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Nnesha (nnesha):
then look at ur previous post and see what i said about perpendicular slope
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
so -3 points @Nnesha
Nnesha (nnesha):
slope of graph 3/1 now flip it
OpenStudy (anonymous):
-1/3 @Nnesha
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Nnesha (nnesha):
right :)
Nnesha (nnesha):
now use slope intercept form equation
y = mx+b
replace m ,x and y by their valeus then solve for b
OpenStudy (anonymous):
what is the value of m @Nnesha
Nnesha (nnesha):
m is slope that you just found
OpenStudy (anonymous):
y =-7 @Nnesha
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OpenStudy (anonymous):
??? @Nnesha
Nnesha (nnesha):
y ??
suppose to b =
OpenStudy (anonymous):
b=-7??/ @Nnesha
Nnesha (nnesha):
hmm nope
OpenStudy (anonymous):
omg please just tell me @Nnesha
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Nnesha (nnesha):
|dw:1422208189690:dw|
that's how you should replace