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Algebra 7 Online
OpenStudy (anonymous):

Simplify the complex fraction [2/(a+b)/(1/a)+(1/b)]

OpenStudy (anonymous):

[2{(1/a) + (1/b)}]/ (a+b)

OpenStudy (anonymous):

okay so when I take the LCD of (a+b) and multiply it by the bottom part of the fraction and its dominators am I distributing the terms or canceling the a or b from the equation. (does this make sense?)

OpenStudy (anonymous):

I just inverted the fraction.. What's LCD (my education is a little different)

OpenStudy (anonymous):

least common dominator when you are trying to get rid of the bottom fractions you can multiply each part by this and you have no fractions

OpenStudy (anonymous):

Im curious what invert the fraction is..

OpenStudy (anonymous):

Example: 2 divided by 1/2 is the same as 2 x 2. You see, I inverted my fraction cuz it was like a fraction upon a fraction

OpenStudy (anonymous):

okay thats so much easier to understand. would you have time to show me a step by step with this problem using that method?

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