Simplify the complex fraction [2/(a+b)/(1/a)+(1/b)]
[2{(1/a) + (1/b)}]/ (a+b)
okay so when I take the LCD of (a+b) and multiply it by the bottom part of the fraction and its dominators am I distributing the terms or canceling the a or b from the equation. (does this make sense?)
I just inverted the fraction.. What's LCD (my education is a little different)
least common dominator when you are trying to get rid of the bottom fractions you can multiply each part by this and you have no fractions
Im curious what invert the fraction is..
Example: 2 divided by 1/2 is the same as 2 x 2. You see, I inverted my fraction cuz it was like a fraction upon a fraction
okay thats so much easier to understand. would you have time to show me a step by step with this problem using that method?
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