simplify the complex rational expression 6x+ 3/y divided by 9x+3/y
I got (2x+1)/(3x+1)
\[(6xy+3)/y \div (9xy+3)/y\] Take reciprocal of 9xy... and it becomes: \[(6xy+3)/y \times y/(9xy+3)\]
ys cancel and it becomes: \[(6xy+3) \div (9xy+3)\] take 3 common and you're left with \[(2xy+1) \div (3xy+1)\]
on the top only the 3 is divided by y. and on the bottom the whole 9x+3 is divided by y
\[6x+(3/y)/(9x+3)/y \]
uh oh, you should've writeen it like that..
yeah getting it to the computer is challenging still.. I wish I could just take a snap shot. lol
Put this in equation form so It's easier to read.
Or draw it.
\[-6/(y+2)(y+3)/[2/(y+3)]+[3/(y+2)]\] better?
The original question was \[\frac{ 6x+3 }{ y }\div \frac{ 9x+3 }{ y }\]
?
\[\frac{ -6 }{ (x+2)(x+3) }\div \frac{ 2 }{ (y+3) }- \frac{ 3 }{ (y+2) }\] these are stacked on top of each other not written out like this
number 8.
for number 8 i got (2x+1) _______ (3x+1)
Not too sure. I'm getting\[\frac{ 6xy+3 }{ 9x+3 }\]
was your LCD y
y/1 for everything
OHHHHHHH you have to take the LCD and multiply 6 by it as well..
Why?
well isnt that what you do when you multiply by the LCD? you have to multiply all parts of the equation
that's what i did. y/1 for everything 6x times y/1=6xy 3/y times y/1=3 9x+3/y times y/1=9x+3
okay.. that makes sense. I now have to go back through this assignment and fix all my answers because I didn't do this. :D
\[\frac{ 2xy+1 }{ 3x+1 }\]
the most simplified answer i can get
after i divide my original answer by 3
ok thanks for your help :)
i am fairly confident about my answer, but i hope someone checks it
Honestly its just a homework assignment so well be going through them tomorrow am in class, so if its not right i can see why and then go from there. Im sure its right. lol your probably in a higher math class then I am anyways haha
im in algebra 2/trig
we were just learning this
everytime i attempt to solve problems l get 9/10 steps correct then one wrong i hope it wasn't in this case
@Nnesha
yes which one ?? give me question
scroll up there is an attachment #8
question 8 n the file right ??
yes
okay lets see
thanks Nnesha
yes @dtan5457 right :)
wooo thank you!
yes that's suppose to be 2xy
bec |dw:1422221640749:dw| oky i just did the top part remember when you multiply variables you should add their exponents so that's why Y^2
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