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Solve the following triangles. If the answer isnt a whole number, round to the hundreths place 1. A=60 degrees, a=1, b=2 I NEED HELP!!
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I dont see a diagram, but I'm assuming A is the angle in between a and b. So use Area = 0.5 x a x b x Sin 60
do you need the area?
no I just have to find angle B, Angle C and side c
Use the Sine and Cosine rules
Law of sines is what we are doing
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the law of sine says \[\frac{\sin(60)}{1} = \frac{\sin(B)}{2}\] solve for B then use angle sum of a triangle to find C then use the law of sine again \[\frac{1}{\sin(60)} = \frac{c}{\sin(C)}\] hope it helps
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