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\[\cos \theta =-\frac{1 }{ 5 } and \tan \theta > 0, find \sin \theta \]
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This figure shows in which quadrants the sine, cosine and tangent are positive or negative. |dw:1422225106598:dw|
Look at your give info. Which quadrant is the answer in?
a.) 4/5 b.) -4/5 c.) \[2\sqrt{6}/5\] d.) \[-2\sqrt{6}/5\]
-1/5 is a negative number so the cos is negative. tan theta > 0 means the number is positive so the tan is positive.
We know we have a negative cosine and a positive tangent. Which quadrant are we dealing with?
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quad 3
|dw:1422226283491:dw| Correct!
so sin is negative?
From that we know the sin is negative. Correct.
Ok. Now we use a triangle.
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that would leave us with B and D then right? cuz those are both negative
|dw:1422226354226:dw|
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