Mathematics
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OpenStudy (henrietepurina):
Algebra 1 question :D
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OpenStudy (henrietepurina):
If -mx^2 + px - c = 0, what is x equal to?
OpenStudy (henrietepurina):
would you know how to help @misty1212 @dtan5457 ?
OpenStudy (misty1212):
HI!! again
OpenStudy (henrietepurina):
heya there again :D
OpenStudy (misty1212):
use the quadratic formula
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OpenStudy (henrietepurina):
ok then
OpenStudy (misty1212):
\[x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\] put \[a=m,b=p,c=-c\] kind of confusing but you can do it
OpenStudy (henrietepurina):
what do you mean? :P
OpenStudy (henrietepurina):
is that the answer :0?
OpenStudy (misty1212):
where you see an "\(a\)" put an \(m\)
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OpenStudy (henrietepurina):
yeah, I did that, and that was one of the answer choices :D
OpenStudy (henrietepurina):
oh wait, it wasn't :(
OpenStudy (henrietepurina):
the bottom part had -2m instead of 2m
OpenStudy (misty1212):
not just that, you have to make all the changes
OpenStudy (henrietepurina):
yeah yeah I understood that...
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OpenStudy (misty1212):
oh right sorry \(a=-m\)
OpenStudy (misty1212):
so the denominator is \(-m\)
OpenStudy (henrietepurina):
ahh! so yeah, that was one of the answer choices... thanks :D
OpenStudy (misty1212):
the numerator is
\[-p\pm\sqrt{p^2-4mc}\]
OpenStudy (henrietepurina):
yeah yeah, I understood that... thanks :D