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Mathematics 15 Online
OpenStudy (henrietepurina):

Algebra 1 question :D Medal + Fan!

OpenStudy (henrietepurina):

If -mx^2 + px - c = 0, what is x equal to?

OpenStudy (henrietepurina):

would you know how to help @misty1212 @dtan5457 ?

OpenStudy (misty1212):

HI!! again

OpenStudy (henrietepurina):

heya there again :D

OpenStudy (misty1212):

use the quadratic formula

OpenStudy (henrietepurina):

ok then

OpenStudy (misty1212):

\[x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\] put \[a=m,b=p,c=-c\] kind of confusing but you can do it

OpenStudy (henrietepurina):

what do you mean? :P

OpenStudy (henrietepurina):

is that the answer :0?

OpenStudy (misty1212):

where you see an "\(a\)" put an \(m\)

OpenStudy (henrietepurina):

yeah, I did that, and that was one of the answer choices :D

OpenStudy (henrietepurina):

oh wait, it wasn't :(

OpenStudy (henrietepurina):

the bottom part had -2m instead of 2m

OpenStudy (misty1212):

not just that, you have to make all the changes

OpenStudy (henrietepurina):

yeah yeah I understood that...

OpenStudy (misty1212):

oh right sorry \(a=-m\)

OpenStudy (misty1212):

so the denominator is \(-m\)

OpenStudy (henrietepurina):

ahh! so yeah, that was one of the answer choices... thanks :D

OpenStudy (misty1212):

the numerator is \[-p\pm\sqrt{p^2-4mc}\]

OpenStudy (henrietepurina):

yeah yeah, I understood that... thanks :D

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