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Given gcd(a,b)=1, prove that gcd(a+b,a-b)=1 or 2.
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A+b=2 but a-b = 0
ssorry if i am wrong but i am 89% sure this is right
Found the proof in my teacher's ppt. gcd(a,b)=1 g=gcd(a+b,a-b) g|a+b and g|a-b g|a+b+(a-b)=2a and g|a+b-(a-b)=2b ->g|gcd(2a+2b) ->g|2 gcd(a,b) ->g|2 ->g=1 or g=2
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