This topic is all about the constant of integration. Please help!!!

A stone thrown upward from the ground attains a height of 100 ft. after 1 second. Find the maximum height it will reach? Use g=32 ft. per sec^2.

Question

This topic is all about the constant of integration. Please help!!!

A stone thrown upward from the ground attains a height of 100 ft. after 1 second. Find the maximum height it will reach? Use g=32 ft. per sec^2.

misty1212 · Answer

HI!!

misty1212 · Answer

i think $g=-32$ that is the acceleration

misty1212 · Answer

then $v(t)=-32t+C$ and you do not know $C$ hmm what can we do?

misty1212 · Answer

we know 
$$h(t)=-16t^2+Ct+0$$ the zero because it was thrown up from the ground, so really 
$$h(t)=-16t^2+C$$ we also know $h(1)=100$ 
use that to solve for $C$

misty1212 · Answer

ooops i meant $$h(t)=-16t^2+Ct$$ that;s better

anonymous · Answer

thanks!