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expand fraction (complex exercise)
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\[2-\frac{ n+2 }{ 2^{n} }+\frac{ n+1 }{ 2^{n+1} }\]
How I can expand the fraction with 2 and \[2^{n}\]
?
Does expand mean to sum ?
yes
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Don't blame me if i misunderstood the question. \[\frac{ 2*2^n }{ 2^n }\] - \[\frac{ n+2 }{ 2^n }\] + \[\frac{ \frac{ n}{ 2 } + \frac{ 1 }{ 2 } }{ 2^n }\] = \[\frac{ 2^{n+1} + 1.5 n + 2.5 }{ 2^n }\]
miscalculated it.
\[\frac{ 2^{n+1} - n - 2 + n/2 + 1/2 }{ 2^n }\]
No I think that 2^n+1=2^n*2 is with exponent rule so the 2^n I must multiplicate with 2. so the exponent sums.
Now the idea came when Im not in failure.
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I apply then I look the solution
Excuse me , clarify your speech.
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