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Physics 16 Online
OpenStudy (anonymous):

PLEASE HELP ME!!!!!!!!!!! Using 6400 km as the radius of Earth, calculate how high above Earth’s surface you would have to be in order to weigh 1/16th of your current weight. Show all work leading to your answer OR describe your solution using 3 -4 complete sentences.

OpenStudy (anonymous):

@ghuczek

OpenStudy (anonymous):

@Kainui

OpenStudy (anonymous):

@kl0723

OpenStudy (anonymous):

Somebody please help me ):

OpenStudy (anonymous):

I'm so frustrated with this I'm literally getting mad..

OpenStudy (anonymous):

you know Weight = mg and now you want to weigh 1/16th.. so its obvious that g --> g/16. So your new question is at what height is g --> 1/16 th of the g on the surface. ya?

OpenStudy (anonymous):

I have no clue.. I'm so lost

OpenStudy (anonymous):

I don't know my current weight so how would I do this??? @1497

OpenStudy (anonymous):

The weight of an object is due to the attractive force of gravity. The gravitational attraction of the earth decreases as the inverse square of the distance from the centre, for points outside the earth.

OpenStudy (anonymous):

@1497 still lost. i have no idea what you're even talking about.. They didn't yeah me how to do this.. I'm the type of person that has to be showed how to do something before I even begin to understand..

OpenStudy (anonymous):

Teach* not yeah

OpenStudy (anonymous):

@jakematt24 lol why are you here

OpenStudy (anonymous):

@Kobek

OpenStudy (anonymous):

@lizzyrockefeller

OpenStudy (anonymous):

@Loser66

OpenStudy (anonymous):

@NoelGreco @nechirwan @NathaliaMA13 @NathanHill1089

OpenStudy (anonymous):

IDK, I THOUGHT IT WOULD BE FUNNY... :)

OpenStudy (anonymous):

@dan815 @bibby please help

OpenStudy (anonymous):

That is the hardest question ive ever seen in my life. good luck. only a geek woud know that one. no offense. lol|dw:1422307509948:dw|

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