Sketch a graph of each function f(x)=(x+3)^2+3
@Zale101 @Preetha
A quadratic equation in vertex form f(x)=(x-h)^2+k Where ( h,k) are the vertex. In this case, where's the vertex in your problem? Point it in the graph below. |dw:1422334414021:dw|
3,3
The k you got it right, but h is not positive 3. If it was then it would be f(x)=(x-(3))^2+3 In your function, you got f(x)=(x+3)^2+3 which is f(x)=(x-(-3))^2+3. h is therefore -3 not +3.
point the vertex on the graph.
do i just plug in the other points
What other points? You mean start plotting points, finding the x and y intercepts?
how do i find them
to find the x-intercept, you set y=0 and solve for x to find the y-intercept, you set x=0 and solve for y.
|dw:1422335096226:dw|
@Zale101
Hint, the parent function is |x| |dw:1422335722495:dw|
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