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OpenStudy (ammarah):
@Zale101 @Preetha
OpenStudy (zale101):
A quadratic equation in vertex form
f(x)=(x-h)^2+k
Where ( h,k) are the vertex. In this case, where's the vertex in your problem? Point it in the graph below.
|dw:1422334414021:dw|
OpenStudy (ammarah):
3,3
OpenStudy (zale101):
The k you got it right, but h is not positive 3. If it was then it would be f(x)=(x-(3))^2+3
In your function, you got f(x)=(x+3)^2+3 which is f(x)=(x-(-3))^2+3. h is therefore -3 not +3.
OpenStudy (zale101):
point the vertex on the graph.
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OpenStudy (ammarah):
do i just plug in the other points
OpenStudy (zale101):
What other points? You mean start plotting points, finding the x and y intercepts?
OpenStudy (ammarah):
how do i find them
OpenStudy (zale101):
to find the x-intercept, you set y=0 and solve for x
to find the y-intercept, you set x=0 and solve for y.
OpenStudy (ammarah):
|dw:1422335096226:dw|
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OpenStudy (ammarah):
@Zale101
OpenStudy (zale101):
Hint, the parent function is |x|
|dw:1422335722495:dw|