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Complete the equation for the linear function whose graph contains the points (2, 5) and (3, 0). y − = (x − 2)
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First we find the slope. \(m = \dfrac{y_2-y_1}{x_2-x_1}\) \(m = \dfrac{0-5}{3-2}\) Subtract & Divide
\[\frac{ -5 }{ 1 } = -5\]
Yes, so we can plug -5 into the equation. \(y - y_1 = m(x- x_1)\) Where 'm' is slope: \(y - y_1 = -5(x - x_1)\) Now we can plug any of the two points into this equation. \(x_1\) is the x-value of the point, and \(y_1\) is the y-value of the point.
So can you plug in (2, 5)?
\[y-5=-5(x-2)\]
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Yes!
That's your answer.
thank you for the help..again lol
No problem :)
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