Question

CALC HELP!! MEDAL!!

Answer 1

pleas explain this problem step by step!!

Answer 2

here http://www.twiddla.com/1960412

Answer 3

can you write the step by step here? it will get a little messy there

Answer 4

please please please @SolomonZelman ive waited over an hour

Answer 5

typical of me, I would try to think of the most elementary approach. They are likely not asking for that, but I will say it.

Answer 6

perl started it if you wanted to see, but had bad conection, you can click on the twiddla link!

Answer 7

wait, what do you mean revolved around y=-2 ?

Answer 8

I am assuming you just need the area of:
https://www.desmos.com/calculator/fuothgc68g

Answer 9

So without the "revolved around y=-2" part:

to give you the region as to picture what functions you are dealing with.
https://www.desmos.com/calculator/m2bq8xo6nn

lets play around without changing the are region.
New picture: https://www.desmos.com/calculator/wh4rlwonev

shift 2 units up:
https://www.desmos.com/calculator/zcarbio8co

So the area of this really is given by: \(\large\color{slate}{\displaystyle\int\limits_{{\Large 1}}^{{\Large 7.389}}\left(\ln(x) {\color{white}{{\LARGE|}}} + {\color{white}{{\LARGE|}}} 2\right)dx}\)

Answer 10

playing is almost never bad.

Answer 11

Oh has 1 mistake

Answer 12

\(\large\color{slate}{\displaystyle\int\limits_{{\Large 1}}^{{\Large 7.389}}\left(-\ln(x) {\color{white}{{\LARGE|}}} + {\color{white}{{\LARGE|}}} 2\right)dx}\)

Answer 13

To see if this makes sense:

\(\large\color{slate}{\displaystyle\int\limits_{{\Large 1}}^{{\Large 7.389}}\left(-\ln(x) {\color{white}{{\LARGE|}}} + {\color{white}{{\LARGE|}}} 2\right)dx}\) that is,

\(\large\color{blue}{~-x\ln(x)+3x~{{\huge |}_{ 1}^{7.389}}}\)

(2x from 2, and the x from integration by parts of ln(x). )

Answer 14

@ganeshie8 would this be correct?

Answer 15

You have to find the volume of solid generated by the highlighted region when rotated by the axis y=-2.