Question

What are the points of discontinuity?

y=(x+1)(x-5)/(x^2+4x+3)

Answer 1

A. x=3, x=-1
B. x=-3, x=-1
C. x=5
D. x=5, x=-1

Answer 2

First, factor the denominator.

Answer 3

equate to zero the factors of the denominator and find the values of x

Answer 4

(x+3)(x+1)

Answer 5

so y=(x+1)(x-5)/(x+3)(x+1)

Answer 6

please don't cancel the x+1, before extracting the restriction that \(\large\color{black}{ \displaystyle x\ne1}\)

Answer 7

Yes, that's a hole, and a point of discontinuity

Answer 8

so what do i do after i factor

Answer 9

The denominator cannot be equal to zero. You just found the zeros of the denominator. That's the answer.

Answer 10

@SolomonZelman