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Solve. Check for extraneous solutions.
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\[2\sqrt{x-1} = \sqrt{26+x}\]
Square both sides to get the radical out.
Understand or no?
yeah i get that part but do i square 2 also. can you show me please?
Yes, you do. \[(2\sqrt{x-1})^2=4(x-1)\]
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\[(\sqrt{26+x})^2=26+x\]
4(x-1)=26+x can you solve for x?
oh yeah so now it will be 4x - 4 = 26 + x 3x = 30 x = 10 THANK YOU SO MUCH NOW I UNDERSTAND
sure thing np
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