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Mathematics 12 Online
OpenStudy (anonymous):

The probabilities of the top-selling menu item in four towns' restaurants being different types of vegetarian and nonvegetarian sandwiches are given in the table. If the restaurant in town 4 has a nonvegetarian sandwich as its top-selling menu item, what is the probability that it is a ham sandwich?

OpenStudy (anonymous):

help (A)20.6% (B)25.3% (C)60.3% (D)62.4%

OpenStudy (perl):

this is a conditional probability problem

OpenStudy (perl):

you are asked, given that you are looking at town 4 non-vegetarian sandwhiches, whats the probability of it being a ham sandwich

OpenStudy (anonymous):

i added the percentages and got 25.9

OpenStudy (perl):

what is the total of town 4 non-veg sandwiches.

OpenStudy (anonymous):

yes you you added the totals right

OpenStudy (perl):

now the probability of just ham veg sandwich in town 4

OpenStudy (anonymous):

what does that mean?

OpenStudy (perl):

ham sandwich in town 4,

OpenStudy (perl):

oh i made a typo

OpenStudy (perl):

it should be 5.86+6.24+6.24+6.33 = 24.67

OpenStudy (anonymous):

yes it is

OpenStudy (anonymous):

but what is the next step

OpenStudy (perl):

so that will be your denominator , the total

OpenStudy (perl):

the numerator is ham sandwich in town 4

OpenStudy (anonymous):

oh im sorry im dumb so whats next

OpenStudy (perl):

probability = (probability of ham sandwich in town 4) / ( probability of non veg. sandwich in town 4 )

OpenStudy (perl):

6.24 / (24.67)

OpenStudy (anonymous):

i got 3.94

OpenStudy (anonymous):

not 20.6

OpenStudy (anonymous):

its b

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