Question

The equation of a circle whose center is at (4, 0) and radius is length 2√(3).

Answer 1

\[(x-h)^2+(y-k)^2=r^2\]
h,k is your center point.

You can square your radius to make it a whole number

Answer 2

so would it be (x-2)^2+(y-5)^2=?

Answer 3

i got 45

Answer 4

You don't really solve for the equation..look