Question

solve x^3 + 20x = -2x^3 - 7x
3x^3 + 27x = 0
3x (x^2 + 9) = 0
3x (x - 3) (x + 3) = 0
x = {-3, 0, 3}
describe and correct the error by step please :)

Answer 1

there is a miss take.....
3x(x^2+9)=0 ...... goood
but 3x(x-3)(x+3)=0 is wrong

Answer 2

it should be 3x(x^2+3^2)=0

Answer 3

your final answer is right

Answer 4

how can someone solve it exactly if it were another type of problem?

Answer 5

x^2+9=0

Answer 6

x^2=-9
x=3i

Answer 7

x=+- 3i

Answer 8

3x (x - 3) (x + 3) = 0
3x[x^2+3x-3x-9]=0
3x(x^2-9)=0 but you have 3x(x^2+9)

Answer 9

you just saved my life! xD thank youuuuu