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Mathematics 9 Online
OpenStudy (anonymous):

I need some help with trig can anyone help?

OpenStudy (anonymous):

OpenStudy (jdoe0001):

posting specifics helps

OpenStudy (anonymous):

I just posted one

OpenStudy (anonymous):

it says to find the following signs of that question

OpenStudy (jdoe0001):

\(\bf cot(\theta)=\cfrac{adjacent}{opposite}=\cfrac{y}{x}=\cfrac{{\color{blue}{ cos}}(\theta)}{{\color{brown}{ sin}}(\theta)} \\ \quad \\ cot(-\theta)=\cfrac{adjacent}{opposite}=\cfrac{y}{x}=\cfrac{{\color{blue}{ cos}}(-\theta)}{{\color{brown}{ sin}}(-\theta)}\implies \cfrac{{\color{blue}{ cos}}(\theta)}{{\color{brown}{ -sin}}(\theta)}\)

OpenStudy (jdoe0001):

using the symmetry identities

OpenStudy (anonymous):

I have the answer key to check my work and I need numbers

OpenStudy (jdoe0001):

though I must say... there isn't really a question per se

OpenStudy (jdoe0001):

well... you don't have an specific number, just a range, that is, the 2nd quadrant

OpenStudy (anonymous):

the answer says 45 degrees and 225 degrees

OpenStudy (jdoe0001):

well... that's coming out of nowhere though since there's just a range, no a question at the most all we could get out of that posting, is a sign and 45 is in the 1st quadrant and 225 in the 3rd....so... dunno how those two got there

OpenStudy (anonymous):

I dont know either but its okay I'll just ask my teacher in class tomorrow

OpenStudy (anonymous):

thanks for trying

OpenStudy (jdoe0001):

yw

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