Algebra 1 help please?? (5.3 x 10^-7)(6 x 10^-5) (x is not a variable it just means to multiply)
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3.18e^-11 Is there answer choices?
nope :( whats the e?
forget the e just put 3.18^-11
don't do this sigh either ^ thats just example
ok so i forgot i was supposed to put it in standard form :(
so I got it wrong, but it lets me try again
So your suppose to put it in standard form?
yes, but it changed out the numbers
The new numbers are...
(3.7 x 10^-4)(3 x 10^-3)
Can you copy and paste the whole question?
no, it won't let me:( but i can type it in word for word, hold on a sec
when you multiply numbers(0r variables) with the same base you add the exponents
Okay that'll work
group like terms and simplify
Evaluate the following expression using exponential rules. Write the result in standard notion.
to put in scientific notation a* 10^n where a is between 0 and 10 , and n is an integer
ok so...............................
um idk
\(\large { \begin{array}{cllll} (5.3\times 10^{-7})(6\times 10^{-5})\\ (5.3\times 10^{-7})(6.0\times 10^{-5}) \end{array} }\) a negative exponent over the 10, means, "move the decimal point to the LEFT that many slots"
so do i first times 5.3 by 6? Then move the decimal 12 places to the left?
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