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For y = 4x + 2x^2 – x^3 show how to find the value for y, when x = 2. I just need help working it out
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when x=2 so you have to replace all x's by 2 and then just solve
substitute 2 into x
solve y=4(2)+2(2)^3-(2)^3 remember to use pemdas
OH, gosh. I totally forgot, thank you both
y=16?
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nope
look at ur original question and try that again
that is 2(2)^2 then -(2)^3
8?
correct :)
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Yay! Thanks!
yayyayay!!good job!! mmy pleasure :)
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