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Trigonometry
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find sec theta if tan theta =7/24 and cos theta < 0.
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do you know which quadrant has tan as positive and cos negative..?
quadrant 3
great so drawing a diagram for quadrant 3 |dw:1422515784503:dw| can you now find c, the hypotenuse using pythagoras?
he said do not draw a triangle to use the identities I think
c=sqrt(a^2+b^2)
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ok then so you need to know \[\sin^2(\theta) + \cos^1(\theta) = 1\] dividing every term by cos^2 gives \[\tan^2(\theta) + 1 = \sec^2(\theta)\] so substituting \[(\frac{7}{24})^2 + 1 = \sec^2(\theta)\] so evaluate this and then take the square root. then use the negative value.
hope it helps
thanks so much I just found where I wrote it all down in my notes !!!
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