Question

Law of cosines

Answer 1

A = 50°, b = 13, c = 6

Answer 2

I got 10.2 ish for a

Answer 3

But when I try to find C its out side of the domain

Answer 4

Does this mean that no triangle can be made?

Answer 5

So you have A = 50, b = 13, c = 6, a=10.2

Answer 6

What about C and B?

Answer 7

Should I just use the law of sines?

Answer 8

arcsin((13sin(50)/10.2))

Answer 9

for B

Answer 10

You may use law of sines to find angle C

Answer 11

\[\large \dfrac{\sin (C)}{6} = \dfrac{\sin(50)}{10.2}\]

Answer 12

B is 77.5 degrees, C is 22.5

Answer 13

but 77.5 + 22.5 + 50 doest equal 180

Answer 14

how did you get C = 22.5 ?

Answer 15

6sin50/10.2 = sin C

Answer 16

yes, keep going..

Answer 17

.450614378 = sin C
arcsin(.450614378 = C
26.8

Answer 18

77.5 + 26.8 + 50 still doesnt equal 180

Answer 19

Is no triangle formed?

Answer 20

Well no triangle can be formed

Answer 21

@ganeshie8

Answer 22

Yolo

Answer 23

Crap I was wrong

Answer 24

im getting below for angles :

C = 27
B = 103

Answer 25

click below for angle C :
http://www.wolframalpha.com/input/?i=arcsin%28+6*%5Cdfrac%7B%5Csin%2850%29%7D%7B10.2335%7D%29

Answer 26

I got 27 for C as well

Answer 27

I didnt got 103 for B

Answer 28

show ur work for B

Answer 29

13sin50/10.2 = sin B

Answer 30

Because sin B / 13 = sin 50 / 10.2

Answer 31

looks good, what do u get for B ?

Answer 32

77.5

Answer 33

thats right! but it wont form a triangle, so subtract it from 180

Answer 34

remember sin(x) = sin(180-x)

Answer 35

Oh