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OpenStudy (anonymous):
If f(x)=x^2+3x+5
What Is? f(3+h)
:D Help please?
11 years ago
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OpenStudy (bibby):
plug in (3+h) everywhere you see x
11 years ago
OpenStudy (anonymous):
solve for h?
11 years ago
OpenStudy (anonymous):
distributive property?
11 years ago
OpenStudy (bibby):
you don't really have to
there are some simplifications you do like \((3+h)^2=3*3+3*h+3*h+h^2\) (you can just use (a+b)^2=a^2+2ab+b^2)
I assume that's what they want you to do
11 years ago
OpenStudy (bibby):
\( f(x)=x^2+3x+5\longrightarrow f(3+h)=(3+h)^2+3(3+h)+5 \)
11 years ago
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OpenStudy (bibby):
yes simplifcation here would involve the distributive property
11 years ago
OpenStudy (bibby):
do you need a little push in the right direction or are you working on it
11 years ago
OpenStudy (anonymous):
kind of i think i'm just messing up the simplification part
11 years ago
OpenStudy (bibby):
show me what you have
11 years ago
OpenStudy (anonymous):
do i apply the distributive property to the beginning f(3+h) so f3+fh?
11 years ago
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OpenStudy (bibby):
no, f(blah blah blah) is just a recipe saying t hat the stuff in the parentheses is what replaces the x in our equation
11 years ago
OpenStudy (bibby):
\(f(3+h)=(3+h)^2+3(3+h)+5\) the left hand side doesn't have to be touched, it's just a statement of equivalence
11 years ago
OpenStudy (anonymous):
so im at \[9h^2+9+3h+5\]
11 years ago
OpenStudy (anonymous):
9h is not ^2 my bad
11 years ago
OpenStudy (anonymous):
but i don't think I am supposed to solve for h...
11 years ago
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OpenStudy (anonymous):
yes
11 years ago
OpenStudy (bibby):
well, to start \((3+h)^2+3(3+h)+5=\\h^2+6h+9+3(3+h)+5=\\h^2+6h+14+9+3h=?\)
11 years ago
OpenStudy (anonymous):
h^2+9h+23
11 years ago
OpenStudy (anonymous):
thank you :(
11 years ago
OpenStudy (bibby):
looks good
11 years ago
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