Question

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Answer 1

you have 2/3rds of the information necessary.
recall the area of the triangle formula \(A=\frac{1}{2}bh\)
you have A, and h

Answer 2

yup

Answer 3

\(\large \frac{16a^2b^4}{4a^2}\)

Answer 4

you're doing something wrong

Answer 5

the division. somehow you're getting 16/4=12

Answer 6

nope. x^m/x^n=x^(m-n), they have to have a common base to do that (hence why the a's get canceled ouut)

Answer 7

yeah
4b^2

Answer 8

no

Answer 9

I meant 4b^4