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please help me solve the radical function: 7-(x+6)^1/2=3 I am not sure how to make a square root on here so I used the 1/2 power
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this is to be an expression and not a function
does this say \[7-\sqrt{x+6}=3\]?
guess we'll never know...
yes it does say that
oh ok
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then since \(7-4=3\) that means \[\sqrt{x+6}=4\]
solve for \(x\) either in your head, or square and get \(x+6=16\)
so I should come up with x=10?
yes you should !
okay thank you very much!
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yw
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