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integral of ((1-x)/(x))^2 dx I mostly need help figuring out u and du.
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oh oh is the square on the whole thinggggg grrr wish i could read >.<
yea it's on the whole thing
\[\Large\rm \int\limits \left(\frac{1-x}{x}\right)^2dx\]Hmm I don't see a u-sub... Expand then simplify I guess?
\[\Large\rm =\int\limits \frac{1}{x^2}-\frac{2}{x}+1~dx\]Something like that?
I think so and then you can integrate take antiderivative on each one
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I see a logarithm
Final answer I get is \[-\frac{ 1 }{ x } - 2\ln(x) +x + C\]
Thanks for the help!
|dw:1422599693491:dw|
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