How do I solve problems like this? "What is the denominator of the sixth term?" 1, 1/8, 1/27, 1/64, ... 1/n^3

Question

anonymous · Answer

$$1, 1/8, 1/27, 1/64, ... 1/n^3$$

anonymous · Answer

@Directrix

freckles · Answer

You have on the bottoms this: 1^3,2^3,3^3,...

freckles · Answer

So the bottom for the sixth term would be?

anonymous · Answer

@freckles Sorry, I'm not sure I know what you mean by that.

freckles · Answer

Denominators is what I was calling bottoms

anonymous · Answer

Oh ok. I still am not sure what you mean. I haven't done any kind of math in a long time and I am just trying to refresh my memory. So I honestly have no idea how to do problems like this.

freckles · Answer

First term=1/1^3
Second term=1/2^3
Third term=1/3^3

freckles · Answer

The only thing that is changing is the base in the denominators 
And it keeps going up by one each time

freckles · Answer

Let me write it another way
1term=1/1^3 
2term=1/2^3 
3term=1/3^3 
So 6term=?

freckles · Answer

Another example the 7th term=1/7^3

freckles · Answer

The 30th term would be 1/30^3 and the denominator of the 30th term would be 30^3