graphing help please, MEDAL. A system of linear inequalities is shown below: x + 2y < -5 x - y > 0 Describe the steps to graph the solution set to the system of inequalities.
someone?? @iGreen ?
you'll want to start with putting it in y=mx+b form.
i know, but i'm not sure how.
Start with the first equation. We want to get rid of that 2 by cancelling it out. We divide the left side by 2 but what we do to one side we must do to the other. so we divide -5 by 2 to get -2.5 This makes our equation x+y<-2.5
all we do with these equations now is move the x y<-x-2.5 -y>x
we graph both of the intercepts.
The first equations intercept is -2.5 and the second one is 0
Since the slope is \[\left(\begin{matrix}1 \\ 1\end{matrix}\right)\] this means you go up one and over one for each one.
x - y > 0 = -y > x ?
it actually translates to -y>x-0 but -0 is non existent so can be removed.
oh, okay ! thank you !
No problem! :)
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